By James W. Hunt, Thomas G. Szymanski
Communications of the ACM,
May 1977,
Vol. 20 No. 5, Pages 350-353
10.1145/359581.359603
Comments
Previously published algorithms for finding the longest common subsequence of two sequences of length n have had a best-case running time of O(n2). An algorithm for this problem is presented which has a running time of O((r + n) log n), where r is the total number of ordered pairs of positions at which the two sequences match. Thus in the worst case the algorithm has a running time of O(n2 log n). However, for those applications where most positions of one sequence match relatively few positions in the other sequence, a running time of O(n log n) can be expected.
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